Tonal Bitcoin

Please note, that all numbers of TBC and its divisions/multipliers are written in Tonal, not decimal. This means that instead of counting 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10-- you count: 0, 1, 2, 3, 4, 5, 6, 7, 8, , 9, , , , , , 10. Some higher-value digits may require installing a font.

Unit	BTC	TBC	Pronunciation
TBCᵇ	0.00000001	0.0001	BitCoin-bong
TBCᵐ	0.00000016	0.001	BitCoin-mill
TBCˢ	0.00000256	0.01	BitCoin-san
TBCᵗ	0.00004096	0.1	BitCoin-ton
TBC	0.00065536	1	BitCoin*
ᵗTBC	0.01048576	10	Ton-BitCoin
ˢTBC	0.16777216	100	San-Bitcoin
ᵐTBC	2.68435456	1000	Mill-BitCoin
ᵇTBC	42.94967296	1,0000	Bong-BitCoin
	2,814,749.76710656	1,0000,0000	Tam-BitCoin

* Tonal BitCoin and Decimal BitCoin can be differentiated by the pronunciation of the numbers. "One bitcoin", "two bitcoin", etc is decimal, but "an bitcoin", "de bitcoin" is tonal.

The total number of Tonal BitCoins ever (analogous to the 21mil BTC) is just over 7.75059 tam-bitcoin.

For more information on the Tonal system in general, please see the book.

Guessing TBC or BTC

Given variable 'value' in base units (uBTCents/TBCᵇ), one can guess whether it is properly Decimal BitCoin or Tonal BitCoin with the following pseudo-code:

if ( ! ( this % 0x10000 ) )
	Choose Tonal BitCoin
if ( ! ( this % 1000000 ) )
	Choose Decimal BitCoin
if ( ! ( this % 0x100 ) )
	Choose Tonal BitCoin

Python

import math

def formatBTC(n, addSign = False):
	s = "%0.2f BTC" % (math.ceil(n * 100) / 100.,)
	if addSign and n >= 0:
		s = "+" + s
	return s

def Bitcoin2BTC(n):
	return n / 100000000.

toTonalDict = dict(((57, u'\ue9d9'), (65, u'\ue9da'), (66, u'\ue9db'), (67, u'\ue9dc'), (68, u'\ue9dd'), (69, u'\ue9de'), (70, u'\ue9df'), (97, u'\ue9da'), (98, u'\ue9db'), (99, u'\ue9dc'), (100, u'\ue9dd'), (101, u'\ue9de'), (102, u'\ue9df')))

def formatTBC(n, addSign = False):
	s = "%x" % n
	n %= 1
	if n:
		s += '.'
		while n:
			n *= 16
			s += "%x" % n
			n %= 1
	s = unicode(s).translate(toTonalDict)
	s += " TBC"
	if addSign and n > 0:
		s = "+" + s
	return s

def Bitcoin2TBC(n):
	return n / 65536.

def formatBitcoin(n, addSign = False):
	if not n % 0x10000:
		return formatTBC(Bitcoin2TBC(n), addSign);
	if not n % 1000000:
		return formatBTC(Bitcoin2BTC(n), addSign);
	if not n % 0x100:
		return formatTBC(Bitcoin2TBC(n), addSign);
	s = "%d uBTCents" % (n,);
	if addSign and n > 0:
		s = "+" + s;
	return s;