Talk:Block hashing algorithm: Difference between revisions
Jrmithdobbs (talk | contribs) Created page with "What is licensing/copyright information on that code? Public domain?" |
Therealplato (talk | contribs) No edit summary |
||
| Line 1: | Line 1: | ||
What is licensing/copyright information on that code? Public domain? | What is licensing/copyright information on that code? Public domain? | ||
"Because transactions aren't hashed directly, hashing a block with 1 transaction takes exactly the same amount of effort as hashing a block with 10,000 transactions." | |||
Doesn't it take more effort to calculate the Merkle root for 10,000 transactions than it does than for 1 transaction? Of course, you only have to do this once per block, but it's misleading. It seems you're using "hashing a block" to specifically mean the (iterative) hash calculation, not the process of block generation. I recommend rewording to : | |||
"These are hashed only indirectly through the Merkle root. Because transactions aren't hashed directly, hashing a block with 1 transaction takes exactly the same amount of effort as hashing a block with 10,000 transactions, once the Merkle root of those transactions is calculated." | |||
Revision as of 23:41, 28 January 2012
What is licensing/copyright information on that code? Public domain?
"Because transactions aren't hashed directly, hashing a block with 1 transaction takes exactly the same amount of effort as hashing a block with 10,000 transactions."
Doesn't it take more effort to calculate the Merkle root for 10,000 transactions than it does than for 1 transaction? Of course, you only have to do this once per block, but it's misleading. It seems you're using "hashing a block" to specifically mean the (iterative) hash calculation, not the process of block generation. I recommend rewording to :
"These are hashed only indirectly through the Merkle root. Because transactions aren't hashed directly, hashing a block with 1 transaction takes exactly the same amount of effort as hashing a block with 10,000 transactions, once the Merkle root of those transactions is calculated."